A) 5 : 7
B) 7 : 4
C) 4 : 7
D) 7 : 5
Correct Answer: D
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\frac{{{a}_{1}}}{{{a}_{2}}}+1}{\frac{{{a}_{1}}}{{{a}_{2}}}-1} \right)}^{2}}\Rightarrow \frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}}=6\] \[\frac{{{a}_{2}}}{{{a}_{1}}}=7:5\]
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