Answer:
(i) Fringe width, \[\beta =\frac{D\lambda }{d}.\] With monochromatic source of shorter wavelength \[\lambda ,\]fringe width \[\beta \]decreases. (ii) At the centre of the screen, the path difference is zero for all the wavelengths. So the central fringe is white. As the violet colour has lowest \[\lambda \] the closest fringe or either side of central white fringe is violet, while the farthest fringe is red. After a few fringes, the fringe pattern becomes indistinct due to large overlapping.
You need to login to perform this action.
You will be redirected in
3 sec