Answer:
As \[{{i}_{p}}+{{r}_{p}}={{90}^{\circ }}\] \[\therefore \] \[{{r}_{p}}=90-{{i}_{p}}={{90}^{\circ }}-{{56.3}^{\circ }}=\mathbf{33}\mathbf{.}{{\mathbf{7}}^{\mathbf{o}}}\]
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