Answer:
(i) Magnifying power of a telescope, \[m=\frac{{{f}_{0}}}{{{f}_{e}}}\] Clearly the magnifying power of a telescope depends on the focal lengths of its objective and eyepiece. (ii) R.P. of a telescope \[=\frac{D}{1.22\lambda }\] Clearly, the resolving power of a telescope depends on the aperture (D) of its objective and wavelength (\[\lambda \]) of the light used.
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