Answer:
Suppose the organ pipe has both ends open. Then its fundamental frequency of vibration will be \[v=\frac{\upsilon }{2L}=\frac{1}{2L}\sqrt{\frac{\gamma P}{\rho }}\] (i) As the temperature increases, the velocity of sound increases, so to fix v constant, the value of L must be increased. (ii) If hydrogen is filled in the pipe in place of air, the value of density \[\rho \] decreases. To keep \[v\] constant, the value of L must be increased. (iii) The pressure has no effect on the velocity of sound. It does not affect resonance.
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