Answer:
(i) The wave reflected from a rigid boundary is \[y(x,t)=-20\sin (-2x-4t)=\mathbf{20sin(2x+4t)}\] (ii) The wave reflected from an open boundary is \[y(x,t)=20\sin (-2x-4t)=-\mathbf{20sin(2}x\mathbf{+4t)}\]
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