A) Reaction is reversed
B) Water soluble \[Ca{{(HC{{O}_{3}})}_{2}}\] is formed
C) Vaporisable calcium derivative is formed
D) None of these
Correct Answer: B
Solution :
\[\underset{\text{lime water}}{\mathop{Ca{{(OH)}_{2}}\ +\ C{{O}_{2}}}}\,\xrightarrow{{}}\ \underset{\begin{smallmatrix} \text{white}\ \\ \text{precipitate}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \end{smallmatrix}}{\mathop{CaC{{O}_{3(S)}}+{{H}_{2}}O}}\,\] \[CaC{{O}_{3}}+C{{O}_{2}}(\text{excess)}+{{H}_{2}}O\xrightarrow{{}}\underset{so\operatorname{lub}le}{\mathop{Ca{{(HC{{O}_{3}})}_{2}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
