A) Ferro-ferricyanide
B) Ferric-ferrocyanide
C) Ferri-ferricyanide
D) None of these
Correct Answer: B
Solution :
\[F{{e}^{3+}}+{{K}_{4}}[Fe{{(CN)}_{6}}]\to \underset{\text{Prussian}\,\,\text{ blue}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{K\left[ Fe[Fe\,{{(CN)}_{6}}] \right]+3{{K}^{+}}}}\,\]You need to login to perform this action.
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