A) Blue precipitate of copper hydroxide is obtained
B) Black precipitate of copper oxide is obtained
C) A deep blue solution is obtained
D) No change is observed
Correct Answer: C
Solution :
\[\underset{(\text{excess)}}{\mathop{4N{{H}_{4}}OH}}\,+CuS{{O}_{4}}\to \left[ Cu{{(N{{H}_{3}})}_{4}} \right]\,S{{O}_{4}}\]\[+4{{H}_{2}}O\]You need to login to perform this action.
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