A) Increase in dissociation of \[{{H}_{2}}S\]
B) Decrease the dissociation of salt solution
C) Decrease the dissociation of \[{{H}_{2}}S\]
D) Increase the dissociation of salt solution
Correct Answer: C
Solution :
HCl suppresses ionisation of weakly dissociated \[{{H}_{2}}S,\] with the result only the ionic product of the sulphides of group II radicals exceed their corresponding solubility product and hence only these are precipitated.You need to login to perform this action.
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