A) Lead chloride
B) Mercurous chloride
C) Mercuric chloride
D) Silver chloride
Correct Answer: B
Solution :
\[H{{g}_{2}}C{{l}_{2}}+2N{{H}_{4}}OH\to \underbrace{N{{H}_{2}}-Hg-Cl}_{{}}+\underset{\text{(Black ppt)}}{\mathop{Hg\,\,\,\,\,}}\,+N{{H}_{4}}Cl+2{{H}_{2}}O\]
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