A) \[Mg\]
B) \[Cd\]
C) \[Bi\]
D) \[Cu\]
Correct Answer: D
Solution :
\[CuC{{l}_{2}}+2HN{{O}_{3}}\,\to \,Cu{{(N{{O}_{3}})}_{2}}+2HCl\] \[Cu{{(N{{O}_{3}})}_{2}}\text{ reacts with }N{{H}_{4}}OH\text{ and gives}\,Cu(N{{H}_{3}})_{4}^{2+}\,\] which has deep blue colour.You need to login to perform this action.
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