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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Wet Test for Basic Radical

  • question_answer
    A solution prepared in conc. \[HCl\] sometimes gives white turbidity even in the absence of 1st group, when water is added to it. It is due to the presence of

    A) \[H{{g}^{2+}}\]

    B) \[S{{b}^{3+}}\]

    C) \[A{{g}^{3+}}\]

    D) \[S{{b}^{3+}}\] or \[B{{i}^{3+}}\] or both

    Correct Answer: D

    Solution :

    As the ionic product of\[S{{b}^{3+}}\] and \[B{{i}^{3+}}\] is very low and \[C{{l}^{-}}\]is present in high concentration, therefore Sb and Bi get precipitated, as \[S{{b}^{3+}}+3C{{l}^{-}}\to SbC{{l}_{3}}\]


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