A) 10 days
B) \[6\frac{12}{13}\]days
C) \[8\frac{2}{11}\]days
D) 18 days
Correct Answer: D
Solution :
| [d] A does \[\frac{2}{5}\]of a work in 9 days Remaining work\[=1-\frac{2}{5}=\frac{3}{5}\] (A + B) together complete\[\frac{3}{5}\]work in 6 days. (A + B)'s one day's work\[=\frac{1}{10}\] A's one day's work\[=\frac{2}{5}\times \frac{1}{9}=\frac{2}{45}\] B's one day's work\[=\frac{1}{10}-\frac{2}{45}=\frac{1}{18}\] Hence, B will complete the work in 18 days. |
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