A) \[5\frac{5}{6}\text{days}\]
B) \[5\frac{1}{4}\text{days}\]
C) \[3\frac{1}{2}\text{days}\]
D) \[3\frac{3}{4}\text{days}\]
Correct Answer: C
Solution :
| [c] As one day work\[=\frac{1}{6}\] B's one day work \[=\frac{1}{12}\] C's one day work\[=\frac{1}{15}\] Initially \[\frac{1}{8}\]of work was done So, the remaining work\[=1-\frac{1}{8}=\frac{7}{8}\] Now, \[\frac{7}{8}\]of the work is done by A and B (A and B)'s one day work \[=\frac{1}{6}+\frac{1}{12}=\frac{2+1}{12}=\frac{13}{12}=\frac{1}{4}\] Let they together take x days to finish the work So, \[\frac{1}{4}\times x=\frac{7}{8}\] \[x=\frac{7\times 4}{8}=\frac{7}{2}=3\frac{1}{2}\text{days}\] |
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