A) 5 J
B) \[\frac{5}{6}J\]
C) 6 J
D) \[75\,J\]
Correct Answer: B
Solution :
\[W=Fs=F\times \frac{1}{2}a{{t}^{2}}\] \[\left[ \text{from}\ s=ut+\frac{1}{2}a{{t}^{2}} \right]\] Þ \[W=F\left[ \frac{1}{2}\left( \frac{F}{m} \right)\ {{t}^{2}} \right]\]\[=\frac{{{F}^{2}}{{t}^{2}}}{2m}=\frac{25\times {{(1)}^{2}}}{2\times 15}=\frac{25}{30}=\frac{5}{6}\ J\]
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