A) 100 J
B) 300 J
C) 50 J
D) 125 J
Correct Answer: D
Solution :
Net force on body\[=\sqrt{{{4}^{2}}+{{3}^{2}}}=5N\] \\[a=F/m=5/10=1/2\,m/{{s}^{2}}\] Kinetic energy = \[\frac{1}{2}m{{v}^{2}}\]\[=\frac{1}{2}m{{(at)}^{2}}=125\,Joule\]
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