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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A force \[\overrightarrow{F\,}=6\hat{i}+2\hat{j}-3\hat{k}\] acts on a particle and produces a displacement of \[\overrightarrow{s\,}=2\hat{i}-3\hat{j}+x\hat{k}.\] If the work done is zero, the value of x is                          [Kerala PMT 2002]

    A)             ? 2      

    B)             1/2

    C)             6         

    D)             2

    Correct Answer: D

    Solution :

                    \[W=\overrightarrow{F}.\overrightarrow{s}=(6\hat{i}+2\hat{j}-3\hat{k}).(2\hat{i}-3\hat{j}+x\hat{k})=0\]             \[12-6-3x=0\] Þ \[x=2\]


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