JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A particle moves from position \[{{\vec{r}}_{1}}=\,3\hat{i}+2\hat{j}-6\hat{k}\] to position \[{{\vec{r}}_{2}}=14\hat{i}+13\hat{j}+9\hat{k}\] under the action of force \[4\hat{i}+\hat{j}+3\hat{k}\,N.\] The work done will be                              [Pb. PMT 2002,03]

    A)             100 J  

    B)             50 J

    C)             200 J  

    D)             75 J

    Correct Answer: A

    Solution :

                    \[W=\overrightarrow{F}.(\overrightarrow{{{r}_{2}}}-\overrightarrow{{{r}_{1}}})=(4\hat{i}+\hat{j}+3\hat{k})(11\hat{i}+11\hat{j}+15\hat{k})\]             \[W=44+11+45=100\,Joule\]


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