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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A force \[(\vec{F})=3\hat{i}+c\hat{j}+2\hat{k}\] acting on a particle causes a displacement: \[(\vec{s})\,=-4\hat{i}+2\hat{j}+3\hat{k}\] in its own direction. If the work done is \[6\,J,\] then the value of \['c'\]is          [CBSE PMT 2002]

    A)             0         

    B)             1

    C)             6         

    D)             12

    Correct Answer: C

    Solution :

                    \[W=(3\hat{i}+c\hat{j}+2\hat{k}).(-4\hat{i}+2\hat{j}+3\hat{k})=6\,Joule\]             \[W=-12+2c+6=6\] Þ \[c=6\]


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