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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A force \[\overrightarrow{F}=(5\hat{i}+4\hat{j})\] N acts on a body and produces a displacement \[\overrightarrow{S}=(6\hat{i}-5\hat{j}+3\hat{k})\]m. The work done will be           [CPMT 2003]

    A)             10 J    

    B)             20 J

    C)                         30 J              

    D)                         40 J

    Correct Answer: A

    Solution :

                    \[W=\overrightarrow{F}.\overrightarrow{s}=(5\hat{i}+4\hat{j}).(6\hat{i}-5\hat{j}+3\hat{k})\]\[=30-20=10\,J\]


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