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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A force \[\vec{F}=(5\hat{i}+3\hat{j}+2\hat{k})N\] is applied over a particle which displaces it from its origin to the point \[\vec{r}=(2\hat{i}-\hat{j})m\]. The work done on the particle in joules is         [AIEEE 2004]

    A)             ? 7      

    B)             +7      

    C)             +10    

    D)             +13

    Correct Answer: B

    Solution :

                    \[W=\overrightarrow{F}.\overrightarrow{r}=(5\hat{i}+3\hat{j}+2\hat{k}).(2\hat{i}-\hat{j})=10-3=7\,J\]


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