A) 4.36 kJ
B) 5.17 Kj
C) 8.91 kJ
D) 9.82 kJ
Correct Answer: B
Solution :
\[W=mg\sin \theta \times s\] \[=2\times {{10}^{3}}\times \sin 15{}^\circ \times 10\] \[=5.17\,kJ\]You need to login to perform this action.
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