JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    Due to a force of \[(6\hat{i}+2\hat{j})N\] the displacement of a body is \[(3\hat{i}-\hat{j})m\], then the work done is             [Orissa JEE 2005]

    A)             16 J    

    B)             12 J

    C)             8 J      

    D)             Zero

    Correct Answer: A

    Solution :

                    Work done \[=\overrightarrow{F}.\overrightarrow{s}\]             \[=(6\hat{i}+2\hat{j})\cdot (3\hat{i}-\hat{j})=6\times 3-2\times 1=18-2=16\,J\]


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