A) 1 : 2 : 3
B) 1 : 4 : 9
C) 1 : 3 : 5
D) 1 : 5 : 3
Correct Answer: C
Solution :
When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third second \[{{h}_{I}}:{{h}_{II}}:{{h}_{III}}=1:3:5:\] [because \[{{h}_{n}}\propto (2n-1)]\] \ Ratio of work done \[mg{{h}_{I}}:mg{{h}_{II}}:mg{{h}_{III}}\]= 1:3:5
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