JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A body moves a distance of 10 m along a straight line under the action of a force of 5 N. If the work done is 25 joules, the angle which the force makes with the direction of motion of the body is     [NCERT 1980; JIPMER 1997; CBSE PMT 1999; BHU 2000; RPMT 2000; Orissa JEE 2002]

    A)             \[0{}^\circ \] 

    B)             \[30{}^\circ \]

    C)             \[60{}^\circ \]           

    D)             \[90{}^\circ \]

    Correct Answer: C

    Solution :

                    \[W=Fs\cos \theta \]Þ \[\cos \theta =\frac{W}{Fs}=\frac{25}{50}=\frac{1}{2}\] Þ \[\theta =60{}^\circ \]


You need to login to perform this action.
You will be redirected in 3 sec spinner