JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Constant Force

  • question_answer
    A force \[F=(5\hat{i}+3\hat{j})\] newton is applied over a particle which displaces it from its origin to the point \[r=(2\hat{i}-1\hat{j})\] metres. The work done on the particle is           [MP PMT 1995; RPET 2003]

    A)             ? 7 joules

    B)               + 13 joules

    C)             + 7 joules

    D)               + 11 joules

    Correct Answer: C

    Solution :

                    \[W=\overrightarrow{F}.\overrightarrow{s}=(5\hat{i}+3\hat{j}).(2\hat{i}-\hat{j})\]= 10 ? 3 = 7 J


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