A) 5.28 J
B) 450 mJ
C) 490 mJ
D) 530 mJ
Correct Answer: A
Solution :
\[v=\frac{dx}{dt}=3-8t+3{{t}^{2}}\] \ \[{{v}_{0}}=3\,m/s\] and \[{{v}_{4}}=19\,m/s\] \[W=\frac{1}{2}m(v_{4}^{2}-v_{0}^{2})\] (According to work energy theorem) \[=\frac{1}{2}\times 0.03\times ({{19}^{2}}-{{3}^{2}})=5.28\,J\]
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