JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1.0 mm, the increase in energy of the wire will be

    A) 0.01 J

    B)                             0.02 J

    C)                 0.04 J    

    D)                 1.00 J

    Correct Answer: A

    Solution :

    Increase in energy \[=\frac{1}{2}\times 20\times 1\times {{10}^{-3}}=0.01J\]


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