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JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    If a spring extends by x on loading, then the energy stored by the spring is (if T is tension in the spring and k is spring constant)                                        [AIIMS 1997]

    A)                 \[\frac{{{T}^{2}}}{2x}\]  

    B)                 \[\frac{{{T}^{2}}}{2k}\]

    C)                 \[\frac{2x}{{{T}^{2}}}\]  

    D)                 \[\frac{2{{T}^{2}}}{k}\]

    Correct Answer: B

    Solution :

    \[U=\frac{{{F}^{2}}}{2K}=\frac{{{T}^{2}}}{2K}\]


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