A) 1 : 2
B) 1 : 4
C) 2 : 1
D) 1 : 1
Correct Answer: A
Solution :
\[W=\frac{1}{2}Fl\] \ \[W\propto l\] (F is constant) \ \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{l}{2l}=\frac{1}{2}\]You need to login to perform this action.
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