A) \[Fl/2AL\]
B) \[FA/2L\]
C) \[FL/2A\]
D) \[FL/2\]
Correct Answer: A
Solution :
Energy stored per unit volume = \[\frac{1}{2}\left( \frac{F}{A} \right)\ \left( \frac{l}{L} \right)\]= \[\frac{Fl}{2AL}\]You need to login to perform this action.
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