A) \[6\times {{10}^{-2}}\,J\]
B) \[4\times {{10}^{-2}}\,J\]
C) \[2\times {{10}^{-2}}\,J\]
D) \[1\times {{10}^{-2}}\,J\]
Correct Answer: C
Solution :
\[W=\frac{YA{{l}^{2}}}{2L}=\frac{2\times {{10}^{10}}\times {{10}^{-6}}\times {{({{10}^{-3}})}^{2}}}{2\times 50\times {{10}^{-2}}}\]\[=2\times {{10}^{-2}}\ J\]You need to login to perform this action.
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