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JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    The work per unit volume to stretch the length by 1% of a wire with cross sectional area of \[1\,m{{m}^{2}}\] will be. \[[Y=9\times {{10}^{11}}\,N/{{m}^{2}}]\]                                       [RPET 1999]

    A)             \[9\times {{10}^{11}}\,J\]

    B)                      \[4.5\times {{10}^{7}}\,J\]

    C)             \[9\times {{10}^{7}}J\]

    D)                      \[4.5\times {{10}^{11}}\,J\]

    Correct Answer: B

    Solution :

                \[U=\frac{1}{2}\times Y\times {{(\text{Strain})}^{2}}=\frac{1}{2}\times 9\times {{10}^{11}}\times {{\left( \frac{1}{100} \right)}^{2}}\]                                              \[=4.5\times {{10}^{7}}\ J\]


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