Answer:
As \[F=kx,\] so \[x=\frac{F}{k}\] For same \[F,{{W}_{A}}=\frac{1}{2}{{k}_{A}}{{x}^{2}}=\frac{1}{2}{{k}_{A}}{{\left( \frac{F}{{{k}_{A}}} \right)}^{2}}=\frac{{{F}^{2}}}{2{{k}_{A}}}\] and \[{{W}_{B}}=\frac{{{F}^{2}}}{2{{k}_{B}}}\] \[\therefore \] \[\frac{{{W}_{A}}}{{{W}_{B}}}=\frac{{{k}_{B}}}{{{k}_{A}}}\] As \[{{k}_{A}}>{{k}_{B}}\] therefore, \[{{W}_{A}}<{{W}_{B}}.\]
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