Answer:
Kinetic energy, \[K=\frac{1}{2}m{{\upsilon }^{2}}=\frac{{{(m\upsilon )}^{2}}}{2m}=\frac{{{p}^{2}}}{2m}\] For constant p, \[K\propto \frac{1}{m}\] Thus the lighter body has more kinetic energy than the heavier body.
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