Answer:
By conservation of momentum, \[m\times \upsilon +m\times 0=m{{\upsilon }_{1}}+m{{\upsilon }_{2}}\] or \[\upsilon ={{\upsilon }_{1}}+{{\upsilon }_{2}}\] or \[\upsilon -{{\upsilon }_{1}}={{\upsilon }_{2}}\] ?(1) By conservation of kinetic energy, \[\frac{1}{2}m{{\upsilon }^{2}}+0=\frac{1}{2}m\upsilon _{1}^{2}+\frac{1}{2}m\upsilon _{2}^{2}\] or \[{{\upsilon }^{2}}=\upsilon _{1}^{2}+\upsilon _{2}^{2}\] or \[(\upsilon +{{\upsilon }_{1}})(\upsilon -{{\upsilon }_{1}})=\upsilon _{2}^{2}\] ?(2) Dividing (2) by (1), we get \[\upsilon +{{\upsilon }_{1}}={{\upsilon }_{2}}\] ?(3) Solving (1) and (3), \[{{\upsilon }_{1}}=0\] and \[{{\upsilon }_{2}}=\upsilon \] As a result of the collision, the moving body comes to a stop and the stationary body begins to move with the speed of the first body.
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