A) 700 ergs
B) 70 ergs
C) 60 ergs
D) 20 ergs
Correct Answer: D
Solution :
Referring figure, work done by the force\[={{W}_{1}}+{{W}_{2}}+{{W}_{3}}+{{W}_{4}}\] where,\[{{W}_{1}}=\]area\[ABCM=1\times 10=10ergs\] \[{{W}_{2}}=\]area\[MDEF=1\times 20=20ergs\] \[{{W}_{3}}=\]area\[FGHI=1\times (-\text{ }20)=-20ergs\] \[{{W}_{4}}=\]area\[IJKL=1\times 10=10ergs\] \[\therefore \]Net work done\[=10+20-20+10\] \[=\mathbf{20}\,\,\mathbf{ergs}\]You need to login to perform this action.
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