A) 12 m/sec and 3600N
B) 14 m/sec and 4900N
C) 16 m/sec and 6400N
D) 18 m/sec and 8100N
Correct Answer: B
Solution :
Since \[\frac{1}{2}m{{v}^{2}}=mgh\] \[\therefore \] \[v=\sqrt{2gh}\] \[=\sqrt{2\times 9\cdot \times 10}=\mathbf{14}\,\,\mathbf{m/sec}\] Now, \[F\cdot s=\frac{1}{2}m{{v}^{2}}\] \[\Rightarrow \] \[F=\frac{m{{v}^{2}}}{2d}=\frac{1\times 196}{2\times 2\times {{10}^{-2}}}\] \[=49000\]NewtonsYou need to login to perform this action.
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