9th Class Science Work and energy Question Bank Work, Energy and Power

  • question_answer
    A block of mass \[20\,\,kg\] is pulled over a smooth inclined plane through \[3\,\,m\] as shown in the figure. The plane makes an angle of \[{{30}^{o}}\] with the base. The force applied is parallel to the base.\[(g=10\,\,m\,\,{{s}^{-2}})\] Assuming that no energy is lost otherwise, what is the gain in the P.E. of the block?

    A) \[30J\]              

    B)        \[20J\]

    C) \[300J\]  

    D)        \[600J\]

    Correct Answer: C

    Solution :

    \[W=F\sin \theta \times S=mg\sin \theta \times S\] \[=20\,\,kg\times 10\,\,m\,\,{{s}^{-2}}\times \sin {{30}^{o}}\times 3\] \[=20\times 10\times \frac{1}{2}\times 3=300\,\,J\]


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