A) 4 mg joules
B) 0.4 mg joules
C) 40 mg joules
D) None of these
Correct Answer: B
Solution :
Difference in \[K.\text{ }E.=\]Difference in\[P.E.\] \[=mgh=2mgr\] \[(\because \,\,h=2r)\] \[=2mg\times 0.2\] \[=\mathbf{0}\mathbf{.4}\,\,\mathbf{mg}\]joulesYou need to login to perform this action.
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