A) \[{{E}_{b}}={{E}_{g}}\]
B) \[{{E}_{b}}<{{E}_{g}}\]
C) \[{{E}_{b}}>{{E}_{g}}\]
D) \[{{E}_{b}}\ge {{E}_{g}}\]
Correct Answer: C
Solution :
\[{{E}_{b}}=\frac{1}{2}m{{v}^{2}},\,\,{{E}_{g}}=\frac{1}{2}M{{V}^{2}}\] Since\[KE\propto {{V}^{2}}\]and\[v>V,\,\,{{E}_{b}}>{{E}_{g}}\]You need to login to perform this action.
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