A) \[\frac{{{L}^{2}}}{2M}\]
B) \[\frac{{{P}^{2}}}{M}\]
C) \[\frac{{{L}^{2}}}{2M{{R}^{2}}}\]
D) \[\frac{1}{2}Mp\]
Correct Answer: C
Solution :
We know\[K.E.=\frac{1}{2}m{{v}^{2}}\], and \[L=mvR\] Substituting for\[v\], we get\[K.E.=\frac{{{L}^{2}}}{2M{{R}^{2}}}\]You need to login to perform this action.
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