A) \[0.25\,\,J\]
B) \[0.50\,\,J\]
C) \[0.75\,\,J\]
D) \[1.25\,\,J\]
Correct Answer: A
Solution :
\[g'=g{{\left( \frac{{{R}_{e}}}{{{R}_{e}}+{{R}_{e}}} \right)}^{2}}=\frac{g}{4}=0.25\,\,m\,\,{{s}^{-2}}\] \[\therefore \]Increase in\[P.E.=mg'h\] \[=0.5\times 0.25\times 2=0.25\,\,J\]You need to login to perform this action.
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