Answer:
We know, \[K.E.\frac{1}{2}m{{v}^{2}}\] Applying the above formula for two cases, we get \[K.E{{.}_{1}}\frac{1}{2}m{{v}^{2}}\] ???..(1) \[K.E{{.}_{2}}=\frac{1}{2}\times 10m\times {{v}^{2}}m=5m{{v}^{2}}\] ???..(2) Dividing equation (1) by (2) we get \[\frac{K.E{{.}_{1}}}{K.E{{.}_{2}}}=\frac{\frac{1}{2}m{{v}^{2}}}{5m{{v}^{2}}}=\frac{1}{10}\] \[\therefore \,\,K.E{{.}_{1}}:K.E{{.}_{2}}=1:10\] Dog Horse mass \[({{m}_{1}})=m\] mass \[({{m}_{2}})=10\,m\] speed \[({{V}_{1}})=V\] speed \[({{V}_{2}})=V\]
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