Answer:
Given, \[m=40\,kgh=1.5\,m\] (i) At highest point K.E. = ? We know, \[K.E.=\frac{1}{2}m{{v}^{2}}\] But, at highest point velocity ?v? is zero \[\therefore K.E.=\frac{1}{2}\times m\times {{0}^{2}}=0\] (ii) At highest point P.E. = ? We know, \[P.E.=mgh\] \[\Rightarrow P.E.=40\times 9.8\times 1.5=588J\]
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