Answer:
Given, \[m=150\,kgP.E.=7350\,J\] \[g=9.8\,\,m/{{s}^{2}}h=?\] We know, \[P.E.=mgh\Rightarrow h=\frac{P.E.}{mg}\] \[\therefore h=\frac{7350}{150\times 9.8}=5\,m\]
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