Answer:
Given, \[V=5\times {{10}^{-8}}{{m}^{3}}h=100m\] \[g=10m/{{s}^{2}}W=?\] \[d={{10}^{3}}kg/{{m}^{3}}\] We know, \[W=mgh\] Formula: \[Density=\frac{mass}{volume}\] \[\Rightarrow mass=density\times Volume\] \[\Rightarrow m={{10}^{3}}\times 5\times {{10}^{-8}}=5\times {{10}^{-5}}kg\] \[\therefore W=5\times {{10}^{-5}}\times 100=5\times {{10}^{-2}}=0.05J\]
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