Answer:
Given, \[m=1\,\,kgt=5s\] \[g=10m/{{s}^{2}}u=0\] \[K.E.=?\] We know, \[K.E.=\frac{1}{2}m{{v}^{2}}\] ???.(1) For this first we have to find ?v? From the relation \[S=ut+\frac{1}{2}g{{t}^{2}}\] we get, \[S=0\times 5+\frac{1}{2}\times 10\times {{(5)}^{2}}=125\,m\] So, we get displacement value now we have to find ?v? value. From the relation, \[{{v}^{2}}-{{u}^{2}}=2gS\] we get, \[{{v}^{2}}-{{0}^{2}}=2\times 10\times 125\] \[\Rightarrow {{v}^{2}}=2500\] Applying the above value in equation (1) \[\because K.E.=\frac{1}{2}\times 4\times 2500=5000J\]
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