Answer:
Given, \[m=10\,kgh=5m\] \[g=10\,m/{{s}^{2}}K.E.=?\] We know, \[K.E.=\frac{1}{2}m{{v}^{2}}\] First we have to find, ?v? From the relation, \[{{v}^{2}}-{{u}^{2}}=2gh\] We get, \[{{v}^{2}}={{0}^{2}}=2\times 10\times 5(\because u=0)\] \[\Rightarrow {{v}^{2}}=100\] \[\therefore K.E.=\frac{1}{2}\times 10\times 100=500J\]
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